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The following information applies to the questions displayed below.]
Two-tailed test One-tailed test
Reject H0 when z ≤ 2.326 Reject H0 when z > 2.326
Fail to reject H0 Reject H0
Question-2
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the interval (, ). |
b. | Compute the value of the test statistic. (Round your answer to 3 decimal places.) |
Value of the test statistic |
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c. | What is your decision regarding the null hypothesis? | ||||
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Question-3
The management of White Industries is considering a new method of assembling its golf cart. The present method requires 42.3 minutes, on the average, to assemble a cart. The mean assembly time for a random sample of 24 carts, using the new method, was 40.6 minutes, and the standard deviation of the sample was 2.7 minutes. Using the .10 level of significance, can we conclude that the assembly time using the new method is faster? |
a. | What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) |
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Reject H0 : μ ≥ 42.3 when the test statistic is |
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b. | Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) |
Value of the test statistic |
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c. What is your decision regarding H0? | |||||||||||||||||||
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( , ). Answer: (-2.571, 2.571) |
b. | Compute the value of the test statistic. (Round your answer to 2 decimal places.) |
| Value of the test statistic |
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c-1. | What is your decision regarding the H0? | |||||||
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c-2. | Can we conclude the mean is different from 100? | |||||||
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d. | Estimate the p-value. | ||
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Question-5
A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.67. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59. Conduct the following test of hypothesis using the .08 significance level. |
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H0 : μ1 ≤ μ2 |
H1 : μ1 > μ2 |
a. | This a |
-tailed test. |
b. | State the decision rule. (Negative values should be indicated by a minus sign. Round your answer to 2 decimal places.) |
The decision rule is to reject H0 if z is |
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c. | Compute the value of the test statistic. (Round your answer to 2 decimal places.) |
Value of the test statistic |
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Answer: 0.61
d. | What is your decision regarding H0? |
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H0. |
e. | What is the p-value? (Round your answer to 4 decimal places.) |
p-value |
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Question-6
A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. |
At the .10 significance level, is there a difference in the population means? | ||
a. | This is a | |
-tailed test. |
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b. The decision rule is to reject if or . (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) | ||
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C. The test statistic is t = . (Round your answer to 3 decimal places.) | ||
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d. What is your decision regarding H0? | ||
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e. | The p-value is |
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Question-7
The null and alternate hypotheses are: |
H0: μ1 ≤ μ2 |
H1: μ1 > μ2 |
A random sample of 20 items from the first population showed a mean of 100 and a standard deviation of 15. A sample of 16 items for the second population showed a mean of 94 and a standard deviation of 8. Use the .05 significant level. |
a. | Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.) |
| Degrees of freedom |
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b. | State the decision rule for .05 significance level. (Round your answer to 3 decimal places.) | |||
| Reject H0 if t> . |
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c. | Compute the value of the test statistic. (Round your answer to 3 decimal places.) | ||
Value of the test statistic |
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d. | What is your decision regarding the null hypothesis? Use the .05 significance level. |
The null hypothesis is |
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Question-8
The following are six observations collected from treatment 1, four observations collected from treatment 2, and five observations collected from treatment 3. Test the hypothesis at the 0.05 significance level that the treatment means are equal. |
Treatment 1 | Treatment 2 | Treatment 3 | |||
9 |
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a. | State the null and the alternate hypothesis. | |
| H0: μ1 = μ2 = μ3 | |
H1 : Treatment means are not all the same. |
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b. | What is the decision rule? (Round your answer to 2 decimal places.) |
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Reject Ho if F > |
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Answer: 3.89
c. | Compute SST, SSE, and SS total. (Round your answers to 2 decimal places.) |
SST = | SSE = | SS total = |
SST = 70.40 , SSE = 82.53 , SS total = 152.93
d. | Complete the ANOVA table. (Round SS, MS and F values to 2 decimal places.) |
| Source | SS | df | MS | F |
| Treatments |
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| Error |
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| 6.88 |
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| Total | 152.93 |
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e. | State your decision regarding the null hypothesis. |
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| Decision: |
Question-9
A stock analyst wants to determine whether there is a difference in the mean rate of return for three types of stock: utility, retail, and banking stocks. The following output is obtained: |
Analysis of Variance
Source DF SS MS F P
Factor 2 86.49 43.25 13.09 0.001
Error 13 42.95 3.30
Total 15 129.44
Level N Mean St. Dev ---------+------------+-------------+--------
Utility 5 17.400 1.916 (------*--------)
Retail 5 11.620 0.356 (------*--------)
Banking 6 15.400 2.356 (------*-------)
Pooled st dev = 1.818 ---------+------------+-------------+--------
a. | Using the .05 level of significance, is there a difference in the mean rate of return among the three types of stock? |
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b. | Can the analyst conclude there is a difference between the mean rates of return for utility and retail stocks? For utility and banking stocks? For banking and retail stocks? Explain. |
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Question- 10
There are three hospitals in the Tulsa, Oklahoma, area. The following data show the number of outpatient surgeries performed on Monday, Tuesday, Wednesday, Thursday, and Friday at each hospital last week. At the 0.05 significance level, can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week? |
| Number of Surgeries Performed | |||
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Day | St. Luke's | St. Vincent | Mercy | |
Monday | 14 | 18 | 24 | |
Tuesday | 20 | 24 | 14 | |
Wednesday | 16 | 22 | 14 | |
Thursday | 18 | 20 | 22 | |
Friday | 20 | 28 | 24 | |
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1. | Set up the null hypothesis and the alternative hypothesis. | ||||
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| Null hypothesis | ||||
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2. | Alternative hypothesis | ||||
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3. | For blocks: | ||||
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4. | Alternative hypothesis | ||||
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5. | State the decision rule for .05 significance level. (Round your answers to 2 decimal places.) |
For Treatment: |
Reject H0 if F> |
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For blocks: |
Reject H0 if F> |
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6. | Complete the ANOVA table. (Round SS, MS and F to 2 decimal places.) |
Source | SS | df | MS | F |
Treatments |
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Blocks |
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Error |
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Total |
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7. | What is your decision regarding the null hypothesis? | ||||
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| The decision for the F value (Treatment) at 0.05 significance is: | ||||
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8. | The decision for the F value (Block) at 0.05 significance is: | ||||
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9. | Can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week? |
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in the mean number of surgeries performed by hospital or by day of the week. |
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Question-11
Mr. James McWhinney, president of Daniel-James Financial Services, believes there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, Mr. McWhinney gathered the following sample information. The X column indicates the number of client contacts last month, and the Y column shows the value of sales ($ thousands) last month for each client sampled. |
Number of | Sales | Number of | Sales | ||||
14 |
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| 30 |
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12 |
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| 48 |
| 90 |
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20 |
| 28 |
| 50 |
| 85 |
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16 |
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| 55 |
| 120 |
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46 |
| 80 |
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| 110 |
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a. | Determine the regression equation. (Negative amounts should be indicated by a minus sign. Do not round intermediate calculations. Round final answers to 2 decimal places.) |
X | Y | ( ) 2 | ( )2 | ( )( ) | ||
14 |
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| 376.36 | 1376.41 | 719.74 |
12 | 14 | −21.4 | −47.1 |
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| 179.56 |
| 443.54 |
16 | 30 |
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46 |
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23 |
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| 967.21 |
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48 | 90 |
| 28.9 | 213.16 |
| 421.94 |
50 | 85 |
| 23.9 | 275.56 |
| 396.74 |
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| 466.56 | 3469.21 | 1,272.24 |
50 | 110.0 | 16.6 | 48.9 |
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b. | Determine the estimated sales if 40 contacts are made.(Do not round intermediate calculations. Round final answers to 2 decimal places.) |
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Answer-12
We are studying mutual bond funds for the purpose of investing in several funds. For this particular study, we want to focus on the assets of a fund and its five-year performance. The question is: Can the five-year rate of return be estimated based on the assets of the fund? Nine mutual funds were selected at random, and their assets and rates of return are shown below. |
| Assets | Return |
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Fund | ($ millions) | (%) | Fund | ($ millions) | (%) |
AARP High Quality Bond | $622.2 | 10.8 | MFS Bond A | $494.5 | 11.6 |
Babson Bond L | 160.4 | 11.3 | Nichols Income | 158.3 | 9.5 |
Compass Capital Fixed Income | 275.7 | 11.4 | T. Rowe Price Short-term | 681.0 | 8.2 |
Galaxy Bond Retail | 433.2 | 9.1 | Thompson Income B | 241.3 | 6.8 |
Keystone Custodian B-1 | 437.9 | 9.2 |
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Click here for the Excel Data File
b-1. | Compute the coefficient of correlation. (Round your answer to 3 decimal places. Negative amount should be indicated by a minus sign.) |
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| r = |
b-2. | Compute the coefficient of determination. (Round your answer to 3 decimal places.) |
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C. Give a description of the degree of association between the variables. | |||||||||||||||||||||||||||||||||||||||||
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Question - 13
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