There are three hospitals in the Tulsa, Oklahoma, area. The following data show the number of outpatient surgeries performed on Monday, Tuesday, Wednesday, Thursday, and Friday at each hospital last week. At the 0.05 significance level, can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week?
Number of Surgeries Performed
Day St. Luke's St. Vincent Mercy
Monday 14 18 24
Tuesday 20 24 14
Wednesday 16 22 14
Thursday 18 20 22
Friday 20 28 24
Click here for the Excel Data File
1. Set up the null hypothesis and the alternative hypothesis.
For Treatment:
Null hypothesis
H0: µSt. Luke's = µSt. Vincent = µMercy
H0: µSt. Luke's ≠ µSt. Vincent ≠ µMercy
2. Alternative hypothesis
H1: Not all means are equal.
H1: All means are equal.
3. For blocks:
Null hypothesis
H0: µMon = µTue = µWed = µThu = µFri
H0: µMon ≠ µTue ≠ µWed ≠ µThu ≠ µFri
4. Alternative hypothesis
H1: All means are equal.
H1: Not all means are equal.
5. State the decision rule for .05 significance level. (Round your answers to 2 decimal places.)
For Treatment:
Reject H0 if F>
For blocks:
Reject H0 if F>
6. Complete the ANOVA table. (Round SS, MS and F to 2 decimal places.)
Source SS df MS F
Treatments
Blocks
Error
Total
7. What is your decision regarding the null hypothesis?
The decision for the F value (Treatment) at 0.05 significance is:
Reject H0
Do not Reject H0
8. The decision for the F value (Block) at 0.05 significance is:
Reject H0
Do not Reject H0
9. Can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week?
There is (Click to select)no differencea difference in the mean number of surgeries performed by hospital or by day of the week.
Number of Surgeries Performed
Day St. Luke's St. Vincent Mercy
Monday 14 18 24
Tuesday 20 24 14
Wednesday 16 22 14
Thursday 18 20 22
Friday 20 28 24
Click here for the Excel Data File
1. Set up the null hypothesis and the alternative hypothesis.
For Treatment:
Null hypothesis
H0: µSt. Luke's = µSt. Vincent = µMercy
H0: µSt. Luke's ≠ µSt. Vincent ≠ µMercy
2. Alternative hypothesis
H1: Not all means are equal.
H1: All means are equal.
3. For blocks:
Null hypothesis
H0: µMon = µTue = µWed = µThu = µFri
H0: µMon ≠ µTue ≠ µWed ≠ µThu ≠ µFri
4. Alternative hypothesis
H1: All means are equal.
H1: Not all means are equal.
5. State the decision rule for .05 significance level. (Round your answers to 2 decimal places.)
For Treatment:
Reject H0 if F>
For blocks:
Reject H0 if F>
6. Complete the ANOVA table. (Round SS, MS and F to 2 decimal places.)
Source SS df MS F
Treatments
Blocks
Error
Total
7. What is your decision regarding the null hypothesis?
The decision for the F value (Treatment) at 0.05 significance is:
Reject H0
Do not Reject H0
8. The decision for the F value (Block) at 0.05 significance is:
Reject H0
Do not Reject H0
9. Can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week?
There is (Click to select)no differencea difference in the mean number of surgeries performed by hospital or by day of the week.
